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Talk:Prime ideal

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WikiProject Mathematics     (Rated Start-Class)
WikiProject Mathematics
This article is within the scope of WikiProject Mathematics, which collaborates on articles related to mathematics.
Mathematics rating: Start Class High Priority Field: Algebra

The previously-listed statement that a subset S of a ring R is a prime ideal iff R\S is closed under multiplication was false. For example, Z\{-1,1} is clearly not an ideal since it's not closed under addition (e.g. 3-2 = 1 is not in it) but {-1,1} certainly is closed under multiplication.

The characterisation of prime ideals at the bottom of the page is incorrect - Dave Benson

I changed the bottom of the page to read that AB is a subset of P instead of AB = P. - Adam Glesser

Cool. Hi Adam. - Dave

[edit] Switching definitions?

We should present this as the definition of a prime ideal:

P is a prime ideal iff it is a proper ideal such that for any ideals A, B, AB \subseteq P \Longrightarrow A \subseteq P \vee B \subseteq P

This definition works in both the commutative and non-commutative cases, and is equivalent to the definitions we're currently using. It's simpler than the one we're using for the non-commutative case, and as simple as the one we're using for the commutative case; it's also more closely analogous to the standard definition of a prime number, with "proper" taking the place of "not unity" and subset taking the place of divisibility. It should lend the article greater unity and clarity. Any objections? — ciphergoth 13:33, 19 August 2008 (UTC)

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